Javascript正则表达式-在子字符串之后获取第一个单词

Question

I have a URL like this:

"/parameterOne/parameterTwo/parameterThree/parameterFour/ParameterFive"

I want to firstly find the substring 'paramaterOne', then find the word immediately after this substring between the slashes which is 'paramterTwo'.

This is the RegEx I have written so far:

\parameterOne\b\/[^/]*[^/]*\/

It returns both 'parameterOne' and 'parameterTwo'. How can I modify this to only return 'parameterTwo' or is there a JavaScript solution that is better?

I do not want to find this parameter by index, it is important I have to find parameterOne first and then find parameterTwo immediately after.

Answer 1

\/parameterOne\b\/([^/]*[^/]*)\/

You can try this and grab the value of group 1 or capture 1.See demo.

https://regex101.com/r/sJ9gM7/99

var re = /\/parameterOne\b\/([^\/]*[^\/]*)\//gm;
var str = '/parameterOne/parameterTwo/parameterThree/parameterFour/ParameterFive';
var m;

if ((m = re.exec(str)) !== null) {
if (m.index === re.lastIndex) {
re.lastIndex++;
}
// View your result using the m-variable.
// eg m[0] etc.
}

or

var myString = "/parameterOne/parameterTwo/parameterThree/parameterFour/ParameterFive";
var myRegexp = /\/parameterOne\b\/([^\/]*[^\/]*)\//gm;
var match = myRegexp.exec(myString);
alert(match[1]);

Answer 2

You can use the javascript split function.

Following code may be taken as example :

"/parameterOne/parameterTwo/parameterThree/parameterFour/ParameterFive".split("/")[2]