Java：查找数组中大于零的最小数

Question

Finding smallest number is easy. I am finding it difficult to find a smallest greater than zero number in an array.

public static int findSmallestOld(int[] arr) {
    int smallest = arr[0];
    for(int i=1; i<arr.length; i++) {
        if(arr[i]<smallest) {
            smallest = arr[i];
        }
    }
    return smallest;
}

Few example inputs could be
{0, 0, 0, 3} output = 3
{0, 1, 0, 4} output = 1

Answer 1

public static int findSmallest(int[] arr) {
    int smallest = Integer.MAX_VALUE;
    for(int i=0; i<arr.length; i++) {
        if(arr[i] > 0 && arr[i]<smallest) {
            smallest = arr[i];
        }
    }
    return smallest;
}

At the end, if smallest == Integer.MAX_VALUE, then all the array is filled of zeros.

Answer 2

change this:

if(arr[i]<smallest)

to

if(arr[i]<smallest && arr[i] > 0) 

otherwise it will be overwritten by any value, whether it is a positive int or not.

Answer 3

public static void main(String[] args) { // write your code here

    int[] numbers = {12,20,85,40,95,54,75,45,50,43,11,9,5,6};
    int temp = numbers[0];
    for (int i = 0; i < numbers.length; i++) {
        if (numbers[i] <  temp) {
            temp = numbers[i] ;

        }

    }
    System.out.println(temp);
}

Answer 4

if(arr[i]<smallest && arr[i]>0) {
    smallest = arr[i];
}