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自引用类:来自 C 接口的具体 python 类

[英]Self-referencing class: concrete python class from C interface

I am trying to design a C interface which could easily be extended in Python (using ctypes ).我正在尝试设计一个可以在 Python 中轻松扩展的 C 接口(使用ctypes )。 I've used the natural idiom in C:我在 C 中使用了自然习语

struct format {
    int (*can_open)(const char *filename);
    struct format * (*open)(const char *filename);
    void (*delete)(struct format *self);
    int (*read)(struct format *self, char *buf, size_t len);
};

It works nicely if I want to extend this interface from C directly:如果我想直接从 C 扩展这个接口,它工作得很好:

struct derived /* concrete implementation */
{
    struct format base;
};

But what I would really like to do, is implement this interface from Python using ctypes.但我真正想做的是使用 ctypes 从 Python 实现这个接口。 Here is what I have so far:这是我到目前为止所拥有的:

CANOPENFUNC   = ctypes.CFUNCTYPE(ctypes.c_int, ctypes.c_char_p)
#OPENFUNC     = ctypes.CFUNCTYPE(ctypes.c_void_p, ctypes.c_char_p)
#OPENFUNC     = ctypes.CFUNCTYPE(ctypes.POINTER( python_format ), ctypes.c_char_p)
#DELETEFUNC   = ctypes.CFUNCTYPE(None, ctypes.c_void_p)
#READFUNC     = ctypes.CFUNCTYPE(ctypes.c_int, ctypes.c_void_p)

def py_canopen_func( string ):
    print "py_canopen_func", string
    return 1

canopen_func   = CANOPENFUNC(py_canopen_func)
#open_func     = OPENFUNC(  py_open_func)
#delete_func   = DELETEFUNC(py_canopen_func)
#read_func     = READFUNC(py_canopen_func)

class python_format(ctypes.Structure):
  _fields_ = (
    ('can_open',  CANOPENFUNC),
    ('open',      OPENFUNC),
    ('delete',    DELETEFUNC),
    ('read',      READFUNC),
  )
  def __init__(self):
    self.can_open = canopen_func
    OPENFUNC    = ctypes.CFUNCTYPE(ctypes.POINTER(python_format), ctypes.c_char_p)
    def py_open_func2( string ):
      print "py_open_func2", string
      return ctypes.byref(self)
    self.open   = OPENFUNC( py_open_func2 )
    #self.delete = delete_func
    #self.read = read_func

Really I am struggling to define the prototype for OPENFUNC here.我真的很努力在这里定义OPENFUNC的原型。 Technically it should be:从技术上讲,它应该是:

OPENFUNC    = ctypes.CFUNCTYPE(ctypes.POINTER(python_format), ctypes.c_char_p)

However I need to define python_format first, which in turns requires a definition for OPENFUNC .但是我需要先定义python_format ,而这又需要定义OPENFUNC

Bonus point: what would be an actual function implementation ?加分点:什么是实际的功能实现? For instance:例如:

def func( str ): return None

or或者

def func( str ): i = python_format(); return ctypes.pointer(i)

both gives me:两者都给了我:

class python_format(ctypes.Structure):
  pass
OPENFUNC = ctypes.CFUNCTYPE(ctypes.POINTER( python_format ), ctypes.c_char_p)
OPENFUNC( func )
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: invalid result type for callback function

Is this related to this other issue ?这与其他问题有关吗? If so should I change my initial C design, since I will not be able to return a pointer to a python_format instance from a callback ?如果是这样,我是否应该更改我的初始 C 设计,因为我将无法从回调返回指向python_format实例的指针?

In the documentation for ctypes.Structure._fields_ it explains how to do this:ctypes.Structure._fields_文档中,它解释了如何执行此操作:

It is possible to define the _fields_ class variable after the class statement that defines the Structure subclass, this allows to create data types that directly or indirectly reference themselves可以在定义 Structure 子类的 class 语句之后定义_fields_类变量,这允许创建直接或间接引用自身的数据类型

This means you can add a:这意味着您可以添加:

class python_format(ctypes.Structure):  # forward declaration
    pass

and then after defining OPENFUNC (and the other function types):然后在定义OPENFUNC (和其他函数类型)之后:

OPENFUNC = ctypes.CFUNCTYPE(ctypes.POINTER( python_format ), ctypes.c_char_p)
DELETEFUNC = etc...

be able to then define python_format._fields_ thusly:然后能够这样定义python_format._fields_

python_format._fields_ = (
    ('can_open',  CANOPENFUNC),
    ('open',      OPENFUNC),
    ('delete',    DELETEFUNC),
    ('read',      READFUNC),
  )

Here's a more complete example based on your code:这是基于您的代码的更完整示例:

import ctypes

class python_format(ctypes.Structure):  # forward declaration
    pass

CANOPENFUNC = ctypes.PYFUNCTYPE(ctypes.c_int, ctypes.c_char_p)
OPENFUNC = ctypes.PYFUNCTYPE(ctypes.c_int,
                                 ctypes.POINTER(python_format),
                                 ctypes.c_char_p)
DELETEFUNC = ctypes.PYFUNCTYPE(None, ctypes.c_void_p)
READFUNC = ctypes.PYFUNCTYPE(ctypes.c_int, ctypes.c_void_p)

def py_canopen_func(self, string):
    print "py_canopen_func", string
    return 1

def py_open_func(self, string):
    print "py_open_func2", string
    # Return types from callbacks cannot be anything other than simple
    # datatypes (c_int, c_float, ..., c_void_p). For other datatypes
    # (STRUCTURE, POINTER, ...), ctypes returns the following error
    # "Invalid result type for callback function"
    # see http://bugs.python.org/issue5710
    return 1  # can't return ctypes.byref(self)

canopen_func = CANOPENFUNC(py_canopen_func)
open_func = OPENFUNC(py_open_func)
#delete_func = DELETEFUNC(py_canopen_func)
#read_func = READFUNC(py_canopen_func)

class python_format(ctypes.Structure):
    python_format._fields_ = (
        ('can_open', CANOPENFUNC),
        ('open', OPENFUNC),
        ('delete', DELETEFUNC),
        ('read', READFUNC),
      )

    def __init__(self):
        self.can_open = canopen_func
        self.open = open_func
        #self.delete = delete_func
        #self.read = read_func

pf = python_format()

In order to have a canonical answer, I'll answer my own question, thanks to @eryksun guidance.为了得到规范的答案,感谢@eryksun 的指导,我将回答我自己的问题。

So first thing first, while this is not clear from the documentation , one cannot return complex type from a callback function.所以首先,虽然文档中并不清楚,但不能从回调函数返回复杂类型。 Therefore, one cannot map a C function pointer:因此,不能映射 C 函数指针:

struct format {
    struct format * (*open)(const char *filename);
};

to

class python_format:
  pass
OPENFUNC    = ctypes.CFUNCTYPE(ctypes.POINTER(python_format), ctypes.c_char_p)
def py_canopen_func( string ):
    return None
open_func     = OPENFUNC(py_open_func)

The above code will gracefully compiles, but at runtime, one gets:上面的代码可以优雅地编译,但在运行时,会得到:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: invalid result type for callback function

The long answer is that:长答案是:

The TypeError message you get when trying to use a non-simple type as the result of a callback is less than helpful.尝试使用非简单类型作为回调的结果时,您收到的 TypeError 消息不太有用。 A callback's result type has to have a setfunc in its StgDictObject (a ctypes extension of the regular PyDictObject).回调的结果类型必须在其 StgDictObject(常规 PyDictObject 的 ctypes 扩展)中有一个 setfunc。 This requirement restricts you to using a simple type such as c_void_p[...]此要求限制您使用简单类型,例如 c_void_p[...]

Therefore the only solution here, as of today, until issue 5710 is fixed is the following:因此,截至今天,在问题 5710得到修复之前,这里唯一的解决方案如下:

class python_format(ctypes.Structure):
  __self_ref = []
  def __init__(self):
    self.open      = self.get_open_func()
  # technically should be a @classmethod but since we are self-referencing
  # ourself, this is just a normal method:
  def get_open_func(self):
    def py_open_func( string ):
      python_format.__self_ref.append( self )
      return ctypes.addressof(self)
    return OPENFUNC( py_open_func )
OPENFUNC     = ctypes.CFUNCTYPE(ctypes.c_void_p, ctypes.c_char_p)

# delay init required because `read_info` requires a forward declaration:
python_format._fields_ = (
    ('open',      OPENFUNC),
  )

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