[英]Grabbing Data from 2 different tables at once without a join php
So I'm making a table where I want to show the 4 data fields, 3 from one table and 1 from another table. 所以我要在一个表中显示4个数据字段,其中一个表显示3个数据字段,另一个表显示1个数据字段。 I have tried using a union and a few other methods and it does not seem to work. 我尝试使用联合和其他一些方法,但它似乎不起作用。 The whole code is given below. 整个代码如下。 A screenshot of the 2 tables I'm trying to get data from is also given below. 下面还提供了我尝试从中获取数据的2个表的屏幕快照。
Tables: http://gyazo.com/a0839ffc4f5c9cb51458b2b01006c745 表格: http : //gyazo.com/a0839ffc4f5c9cb51458b2b01006c745
What I've been trying(sql not php code): 我一直在尝试(SQL不是PHP代码):
SELECT FirstName, LastName, Rating FROM guest WHERE Rating = 5 UNION ALL SELECT Suburb FROM suburb WHERE Suburb = 'Booragoon';
This is the PHP code : 这是PHP代码:
<?php
echo "<table style = 'border; solid 1px black;'>"
echo "<tr><th>First Name</th><th>Last Name</th><th>Suburb</th><th>Rating</th></tr>";
class TableRows extends RecursiveInteratorInterator {
function __construct($it) {
parent::__construct($it, self::LEAVES_ONLY);
}
function current() {
return "<td style='width:160px;border:1px solid black;'>" . parent::curren(). "</td>";
}
function beginChildren(){
echo "<tr>";
}
function endChildren() {
echo "</tr>" . "\n";
}
}
$Suburb = $_POST['InputSuburb'];
$Rating = $_POST['InputRating'];
$username = 'root';
$password = '';
$conn = new PDO('mysql:host=localhost;dbname=pizza_shop' $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $conn->prepare//where the command is going
$stmt->bindParam('Suburb',$Suburb, PDO::PARAM_STR);
$stmt->execute();
?>
you need a simple join condition on postcode and the where condition what you want to. 您需要一个关于邮政编码的简单加入条件以及您想要的where条件。
SELECT FirstName, LastName, Rating,subrup FROM guest inner join suburb
on guest.postcodefk = suburb.postcode
WHERE Suburb = 'Booragoon' and Rating = 5;
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