如何找到输入回路中的最低编号？

Question

I have to write a code that tells the user to input 4 number (they could be decimal) and print the average and lowest of those numbers.

So far I have managed to get the average, but I'm having trouble getting the lowest of the numbers.

int iteration = 0;
    float number;
    float total = 0;
    float average;
    float lowest;


    Scanner input = new Scanner(System.in);

    while (iteration < 4){
        System.out.println("Enter score : ");
        number = input.nextFloat();

        iteration++;

        total += number;


        }

    average = total / 4;
    System.out.println("The average is: " + average);

Answer 1

You can initialize your lowest with value Float.MAX_VALUE , everytime the user inputs a value, you compare your lowest with the input value and assign the new smaller value to your lowest.

int iteration = 0;
float number;
float total = 0;
float average;
float lowest = Float.MAX_VALUE;


Scanner input = new Scanner(System.in);

while (iteration < 4){
    System.out.println("Enter score : ");
    number = input.nextFloat();

    iteration++;

    total += number;

    if(number < lowest){
        lowest = number;
    }

}

average = total / 4;
System.out.println("The average is: " + average);
System.out.println("The minimum is: " + lowest);

Answer 2

Try this:

float minValue = Double.MAX_VALUE;
while(...){
   ...
   number = input.nextFloat();
   minValue = Math.min(minValue, number);
   ...
}

Hope this will help you:).

Answer 3

Initially define float lowest = some big no . Now Every time you enter an input compare it with the lowest . If the input is less than lowest assign it as lowest , otherwise don't change lowest .

Answer 4

As said by Olli Zi you can get the min value by using just a simple function Math.min().Moreover for detailed understanding i am providing the code as well.

    int iteration = 0;
    float number[]=new float[4];
    float total = 0;
    float average;
    float lowest;


    Scanner input = new Scanner(System.in);

    while (iteration < 4){
        System.out.println("Enter score : ");
        number[iteration] = input.nextFloat();
        total += number[iteration];

        iteration=iteration+1;


    }

    average = total / 4;
    System.out.println("The average is: " + average);


    System.out.println(Math.min(Math.min(number[0],number[1]), Math.min(number[2],number[3]))); 

Hope it helps!