[英]how to extract parameter(specified pattern string) from string in javascript
I need to extract parameter name from the url path. 我需要从网址路径中提取参数名称。 parameters are inside {} or follow the first ?(questionmark) or follow & mark in the url. 参数位于{}内,或跟随第一个?(问号)或跟随url中的&标记。
the url path need to be extracted is in such format : 需要提取的url路径是这样的格式:
/tt/{pa}/{pb}/?p1=9888&p2=9&p3=98
thus the parameters are pa
, pb
, p1
, p1
, p3
因此参数是pa
, pb
, p1
, p1
, p3
Quickest way I can think of is this: 我能想到的最快方法是:
[{?&][^}=]+
Now I'm also capturing the {
or ?
现在,我还在捕获{
或?
or &
character preceding it, so you'd have to cut that off afterwards: 或&
之前的字符,因此您之后必须将其删除:
var inp = '/tt/{pa}/{pb}/?p1=9888&p2=9&p3=98' var found = inp.match(/[{?&][^}=]+/g).map(function(p){ return p.substring(1); }); document.write(found.join('<br />'));
And if you expect something like /tt/{pa=}/{pb}/?p1={9888&p2=9&p3=98
where pa=
is a valid param name and/or {9888
is a valid value, you'd be in trouble. 而且,如果您希望输入类似/tt/{pa=}/{pb}/?p1={9888&p2=9&p3=98
,其中pa=
是有效的参数名称和/或{9888
是有效的值,麻烦。 But I doubt this is a serious limitation. 但是我怀疑这是一个严重的限制。
Simple example for extracting separately search variables and variables from path: 从路径中分别提取搜索变量和变量的简单示例:
function extractSearch(search) {
var result = {};
search = search || window.location.search;
if (search.length) {
search = search.substr(1).split('&');
for (var i = 0; i < search.length; i++) {
search[i] = search[i].split('=');
result[decodeURIComponent(search[i][0])] = decodeURIComponent(search[i][1]);
}
}
return result;
}
function extractFromPath(pattern, url) {
var keys = [],
result = {},
i;
url = url || window.location.pathname;
pattern = pattern.replace(/{([^}]+)}/g, function($0, $1) {
keys.push($1);
return '([^/]+)';
});
pattern = url.match(new RegExp('^' + pattern));
for (i = 0; i < keys.length; i++) {
result[keys[i]] = pattern[i + 1];
}
return result;
}
Example of use: 使用示例:
// Object {a: "10", b: "20"}
extractSearch('?a=10&b=20');
// Object {pa: "1", pb: "2"}
extractFromPath('/tt/{pa}/{pb}', '/tt/1/2/?p1=9888&p2=9&p3=98');
Eventually you can combine it by: 最终,您可以通过以下方式将其组合:
function getParameters(pattern, path) {
var result,
tmp;
path = path.split('?');
result = extractFromPath(pattern, path[0]);
if (path[1] !== void 0) {
tmp = extractSearch('?' + path[1]);
for (var param in tmp) {
result[param] = tmp[param];
}
}
return result;
}
// Object {pa: "1", pb: "2", a: "10", b: "20"}
getParameters('/tt/{pa}/{pb}', '/tt/1/2?a=10&b=20');
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.