[英]Get bigint from Microsoft SQL Server with SOCI
I am trying to get a bigint
value (named "NUM" in my example) that comes from my database (Microsoft SQL Server). 我试图获取来自数据库(Microsoft SQL Server)的
bigint
值(在本示例中为“ NUM”)。 In the following code, I am trying to get it as an int
even if I know that an int
is smaller than a bigint
but the cast always fails. 在以下代码中,即使我知道一个
int
小于bigint
但我的转换总是失败,我仍试图将它作为int
进行获取。 I also tried to get it as a long long int
and as some other types of variable but I am always getting the same problem at runtime as shown below. 我还尝试将它作为
long long int
以及其他一些类型的变量来获取,但是在运行时我总是遇到相同的问题,如下所示。
try
{
session sql(odbc, "...");
rowset<row> rs = (sql.prepare << "SELECT MAX(NUM) AS MAX_NUM FROM T1");
for (rowset<row>::const_iterator it = rs.begin(); it != rs.end(); ++it)
{
row const& row = *it;
cout << "MAX_NUM: " << row.get<int>("MAX_NUM") << endl;
}
}
catch (exception const &e)
{
cerr << "Error: " << e.what() << '\n';
}
I have also tried the following getters: 我还尝试了以下吸气剂:
cout << "MAX_NUM: " << row.get<long>("MAX_NUM") << endl;
cout << "MAX_NUM: " << row.get<long long>("MAX_NUM") << endl;
cout << "MAX_NUM: " << row.get<long long int>("MAX_NUM") << endl;
All my tests print the same error when I run my application: 运行我的应用程序时,我所有的测试都输出相同的错误:
Error: std::bad_cast
My question is : What is the correct way to get this value ? 我的问题是:获得此价值的正确方法是什么?
我不知道这是否是最好的解决方案,但这是我发现的唯一可行的解决方案:
cout << "MAX_NUM: " << row.get<double>("MAX_NUM") << endl;
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