[英]How do I disable one tab in a QTabWidget?
I have a QTabWidget
called tabWidget. 我有一个QTabWidget
称为tabWidget。 It has three tabs: "Basic", "Advanced", and "Current Structure". 它有三个选项卡:“基本”,“高级”和“当前结构”。 The tabs are displayed in the widget in that order. 选项卡按顺序显示在窗口小部件中。
I want to disable the "Advanced" tab whenever the Boolean result
is false. 我想在布尔result
为false时禁用“高级”选项卡。 I thought it would be as simple as this code: 我以为它会像这段代码一样简单:
bool result = false;
if (result == false)
{
tabWidget->widget(1)->setDisabled(true);
}
Unfortunately, this code does not disable the tab, it remains enabled even when I check it: 不幸的是,此代码不会禁用该选项卡,即使我检查它也会保持启用状态:
tabWidget->tabBar()->isTabEnabled(1); // This returns true
Why doesn't the tab become disabled? 为什么标签不会被禁用? Is there another way to do it? 还有另一种方法吗?
I am using Qt 5.4.0. 我使用的是Qt 5.4.0。
You can enable/disable individual tabs in a QTabWidget using the member function setTabEnabled(int index, bool enable) . 您可以使用成员函数setTabEnabled(int index,bool enable)启用/禁用QTabWidget中的各个选项卡。
Based on your code snippet, it would look like this: 根据您的代码段,它看起来像这样:
bool result = false;
if (result == false)
{
tabWidget->setTabEnabled(1, false);
}
You can't, not this way. 你不能,不是这样。
You have to iterate through all the children in the Page and disable them. 您必须遍历页面中的所有子项并禁用它们。
Something like this: 像这样的东西:
QList<QWidget*> list = parentWidget->findChildren<QWidget*>() ;
foreach( QWidget* w, list ) {
w->setEnabled( false ) ;
}
You could disable the layout of the tab. 您可以禁用选项卡的布局。
bool result = false;
if (result == false)
{
tabWidget->widget(1)->layout()->setDisabled(true);
}
如果您使用Qt Widgets应用程序模板,而高级选项卡的名称是tabAdvanced
(您可以在Object Inspector中检查名称),这应该有效:
ui->tabAdvanced->setEnabled(false);
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