C++ cout 十六进制值？

Question

I want to do:

int a = 255; 
cout << a;

and have it show FF in the output, how would I do this?

Answer 1

Use:

#include <iostream>

...

std::cout << std::hex << a;

There are many other options to control the exact formatting of the output number , such as leading zeros and upper/lower case.

Answer 2

std::hex is defined in <ios> which is included by <iostream> . But to use things like std::setprecision/std::setw/std::setfill /etc you have to include <iomanip> .

Answer 3

To manipulate the stream to print in hexadecimal use the hex manipulator:

cout << hex << a;

By default the hexadecimal characters are output in lowercase. To change it to uppercase use the uppercase manipulator:

cout << hex << uppercase << a;

To later change the output back to lowercase, use the nouppercase manipulator:

cout << nouppercase << b;

Answer 4

如果要打印单个十六进制数，然后恢复为十进制数，可以使用以下命令：

std::cout << std::hex << num << std::dec << std::endl;

Answer 5

std::hex gets you the hex formatting, but it is a stateful option, meaning you need to save and restore state or it will impact all future output.

Naively switching back to std::dec is only good if that's where the flags were before, which may not be the case, particularly if you're writing a library.

#include <iostream>
#include <ios>

...

std::ios_base::fmtflags f( cout.flags() );  // save flags state
std::cout << std::hex << a;
cout.flags( f );  // restore flags state

This combines Greg Hewgill's answer and info from another question .

Answer 6

I understand this isn't what OP asked for, but I still think it is worth to point out how to do it with printf. I almost always prefer using it over std::cout (even with no previous C background).

printf("%.2X", a);

'2' defines the precision, 'X' or 'x' defines case.

Answer 7

There are different kinds of flags & masks you can use as well. Please refer http://www.cplusplus.com/reference/iostream/ios_base/setf/ for more information.

#include <iostream>
using namespace std;

int main()
{
    int num = 255;
    cout.setf(ios::hex, ios::basefield);
    cout << "Hex: " << num << endl;

    cout.unsetf(ios::hex);
    cout << "Original format: " << num << endl;

    return 0;
}

Answer 8

Use std::uppercase and std::hex to format integer variable a to be displayed in hexadecimal format.

#include <iostream>
int main() {
   int a = 255;

   // Formatting Integer
   std::cout << std::uppercase << std::hex << a << std::endl; // Output: FF
   std::cout << std::showbase  << std::hex << a << std::endl; // Output: 0XFF
   std::cout << std::nouppercase << std::showbase  << std::hex << a << std::endl; // Output: 0xff

   return 0;
}

Answer 9

C++20 std::format

This is now the cleanest method in my opinion, as it does not pollute std::cout state with std::hex :

main.cpp

#include <format>
#include <string>

int main() {
    std::cout << std::format("{:x} {:#x} {}\n", 16, 17, 18);
}

Expected output:

10 0x11 18

Not yet implemented on GCC 10.0.1, Ubuntu 20.04.

But the awesome library that became C++20 and should be the same worked once installed with:

git clone https://github.com/fmtlib/fmt
cd fmt
git checkout 061e364b25b5e5ca7cf50dd25282892922375ddc
mkdir build
cmake ..
sudo make install

main2.cpp

#include <fmt/core.h>
#include <iostream>

int main() {
    std::cout << fmt::format("{:x} {:#x} {}\n", 16, 17, 18);
}

Compile and run:

g++ -ggdb3 -O0 -std=c++11 -Wall -Wextra -pedantic -o main2.out main2.cpp -lfmt
./main2.out

Documented at:

• https://en.cppreference.com/w/cpp/utility/format/format
• https://en.cppreference.com/w/cpp/utility/format/formatter#Standard_format_specification

More info at: std::string formatting like sprintf

Pre-C++20: cleanly print and restore std::cout to previous state

main.cpp

#include <iostream>
#include <string>

int main() {
    std::ios oldState(nullptr);
    oldState.copyfmt(std::cout);
    std::cout << std::hex;
    std::cout << 16 << std::endl;
    std::cout.copyfmt(oldState);
    std::cout << 17 << std::endl;
}

Compile and run:

g++ -ggdb3 -O0 -std=c++11 -Wall -Wextra -pedantic -o main.out main.cpp
./main.out

Output:

10
17

More details: Restore the state of std::cout after manipulating it

Tested on GCC 10.0.1, Ubuntu 20.04.

Answer 10

How are you!

#include <iostream>
#include <iomanip>

unsigned char buf0[] = {4, 85, 250, 206};
for (int i = 0;i < sizeof buf0 / sizeof buf0[0]; i++) {
    std::cout << std::setfill('0') 
              << std::setw(2) 
              << std::uppercase 
              << std::hex << (0xFF & buf0[i]) << " ";
}