各种正则表达式验证

Question

I'm new to regex. I have an array (call it arr1) with assorted values. I am trying to validate that it has the following format for its elements with arr1[x] provided as an example

arr1[x] = "item1, item2, item3, item4, item5":

item 1 - "abcdef" (variable number of letters) or "abcdef asdf" (variable number of letters separated by one whitespace character)
item 2 - "abcdef" (variable number of letters) or "abcdef asdf" (variable number of letters separated by one whitespace character)
item 3 - "12345678" (eight digits)
item 4 - "123 456 7890" (telephone number with 3 digits followed by 3 digits followed by 4 digits with two whitespace characters as shown)

Here is a snippet of what I have for phone number validation (not sure how the second line works - got it from a different SO thread):

function f(s) {
  var s2 = (""+s).replace(/\D/g, '');
  var m = s2.match(/^(\d{3})(\d{3})(\d{4})$/);
}

Thanks in advance for any assistance.

Answer 1

You can try this regex to account for all your cases:

^(?:[a-z]+(?: [a-z]+)?|\d{8}|\d{3} \d{3} \d{4})$

Use it with i option, eg:

var re = /^(?:[a-z]+(?: [a-z]+)?|\d{8}|\d{3} \d{3} \d{4})$/i; 
if (re.exec(s) !== null) {
    return true;
}

Have a look at the demo .

 var re = /^(?:[az]+(?: [az]+)?|\\d{8}|\\d{3} \\d{3} \\d{4})$/i; var str = 'abcdef'; if (re.exec(str) !== null) { alert(true); }