逐行打印python列表

Question

How can I get the results of my print onto new lines? The list being printed is a first name, surname and email address, so I want each one on a new line.

import csv

f = open('attendees1.csv')
csv_f = csv.reader(f)

attendee_details = []

for row in csv_f:
    attendee_details.append(row[0:4])



sortedlist =[sorted(attendee_details, key=lambda x:x[0])]

print (sortedlist)

Answer 1

print('\n'.join(map(str, sortedlist)))

This will work for all lists. If the list already consists of strings, the map is not needed.

Answer 2

Since you're using Python 3, you can also do this:

print(*sortedlist, sep='\n')

This unpacks the list and sends each element as an argument to print() , with '\\n' as a separator.

Answer 3

Use a for loop. ie, replace the last two lines with this

for i in sorted(attendee_details, key=lambda x:x[0]):
    print(i)

Note that

sortedlist =[sorted(attendee_details, key=lambda x:x[0])]

line of code will create list of list.

Answer 4

最简单的方法如下：

print(*sorted(runnerup), sep='\n')