正则表达式Java扫描仪分隔符

Question

I am trying to read this pattern... What is the Scanner.useDelimiter for this?

This input is:

489 490-1; 491-1; 492-1; 493-1; 494-1; 495-1; 496-1; 497-1; 498-1; 499-1; 500-1;
490 491-1; 492-1; 493-1; 494-1; 495-1; 496-1; 497-1; 498-1; 499-1; 500-1;
491 492-1; 493-1; 494-1; 495-1; 496-1; 497-1; 498-1; 499-1; 500-1;
492 493-1; 494-1; 495-1; 496-1; 497-1; 498-1; 499-1; 500-1;
493 494-1; 495-1; 496-1; 497-1; 498-1; 499-1; 500-1;
494 495-1; 496-1; 497-1; 498-1; 499-1; 500-1;
495 496-1; 497-1; 498-1; 499-1; 500-1;
496 497-1; 498-1; 499-1; 500-1;
497 498-1; 499-1; 500-1;

what I need of output is like:

489

490

1

491

1

492

1

493

1

I tried this delimiter but it didn't work:
Scanner(readerFile).useDelimiter("\\\\s*-\\\\s*|;\\\\s*|\\\\s*");

Answer 1

基本的想法似乎是拆分任何非数字的东西，所以试试这个：

Scanner(readerFile).useDelimiter("[^0-9]+");