如何避免视图模型的冗余属性

Question

I have an interface from which my model and viewmodel implement.I have a list property in interface which model implements as list but for some reasons I need to use observable collection in view model.How can I implement same property with use of observable collection.Here is my sample code,

public  class MyObject
{
    public string Property1 { get; set; }
     public string Property1 { get; set; }
}

public interface IFoo
{
    List<MyObject> MyList { get; set; }
}


public class Model : IFoo
{
    private List<MyObject> mMyList;

    public List<MyObject> MyList
    {
        get { return mMyList; }
        set { mMyList = value; }
    }
}

public class ViewModel : IFoo
{

    // I want 
    //ObservableCollection<string> Mylist 
    //for view purpose,How can I use the same property from interface 


}

Answer 1

Stop being so demanding. In your interfaces, I mean.

public interface IFoo
{
    IList<MyObject> MyList { get; set; }
}

And use an OC behind the scenes

ObservableCollection implements IList, so you can easily

public class Bar : IFoo
{
    public IList<MyObject> MyList {get; private set;}
    public Bar()
    {
        MyList = new ObservableCollection<MyObject>();   
    //snip

The Binding will know our secret and act accordingly.