[英]Swift: taking reference of object's property with ampersand (&) causing compiler error
This is a rather straightforward issue. 这是一个相当简单的问题。 Consider an array:
考虑一个数组:
var array = [1, 2, 3, 4, 5, 6, 7]
I wish to swap the first and the last element of the array, using the standard swap
function: 我希望使用标准
swap
功能swap
数组的第一个和最后一个元素:
swap(&array[0], &array[array.count - 1])
However there exists another way to obtain the first and last elements of an array, which is to use Array
's built-in properties first
and last
. 但是,存在另一种获取数组的第一个和最后一个元素的方法,即使用
Array
的内置属性first
和last
。 It follows that this code should also work: 因此,该代码也应起作用:
swap(&array.first!, &array.last!)
However this time the compiler complains that Type of expression is ambiguous without more context
. 但是,这一次编译器抱怨
Type of expression is ambiguous without more context
。 I wonder how I can modify the expression so that the compiler can parse it correctly. 我不知道如何修改表达式,以便编译器可以正确解析它。
first
is a read-only property, therefore you cannot modify the array through array.first
. first
是一个只读属性,因此您不能通过array.first
修改数组。
swap(&array[0], &array[array.count - 1])
works because subscript()
of mutable collection types has both setter and getter. 之所以起作用,是因为可变集合类型的
subscript()
具有setter和getter。
Not that I recommend it, but if you define your own read-write properties 我不建议这样做,但是如果您定义自己的读写属性
extension Array {
var myFirst: T {
get { return self[0] }
set { self[0] = newValue }
}
var myLast: T {
get { return self[count - 1] }
set { self[count - 1] = newValue }
}
}
(which assume that the array it not empty) then (假设该数组不为空)然后
swap(&array.myFirst, &array.myLast)
works as expected. 如预期般运作。
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