从 ruby​​ 中的字符串中提取和删除子字符串

Question

I have a string as below

"/br/watch/123456"

I need to remove /br and extract only /watch/123456. what is the best way to achieve it in ruby.

Answer 1

You can use sub to remove first occurrence of /br from string, else gsub to remove all occurrences

"/br/watch/123456".sub("/br","")
# => "/watch/123456"

Answer 2

Use sub. sub helps to do a single replacement on strings. The below code will remove the /br sub-string only if it's present at the start.

> "/br/watch/123456".sub(/^\/br/, '')
=> "/watch/123456"

Answer 3

If it's always three characters that should be removed you can.

"/br/watch/123456"[3..-1]

or more verbose and probably slower

"/br/watch/123456".chars.drop(3).join