简体   繁体   English

连接具有相同字段名称的2个表

[英]Join 2 tables with same field names

I have 2 tables : 我有2张桌子:

authors
+-----------+--------------+------+-----+
| Field     | Type         | Null | Key |
+-----------+--------------+------+-----+
| id        | int(6)       | NO   | PRI | 
| name      | varchar(255) | NO   |     |
| age       | varchar(255) | NO   |     |
+-----------+--------------+------+-----+

books
+-----------+--------------+------+-----+
| Field     | Type         | Null | Key |
+-----------+--------------+------+-----+
| id        | int(6)       | NO   | PRI | 
| name      | varchar(255) | NO   |     |
| pub_date  | datetime     | NO   |     |
| author_id | int(11)      | YES  | MUL | 
+-----------+--------------+------+-----+

I'd like to get the author information with his last written book information. 我想获得作者信息以及他最近的书面著作信息。 Something that would look like that : 看起来像这样的东西:

{
  name:"Tolkien",
  age:null,
  last_book:{
    name:"The Children of Hurin",
    pub_date:"2007"
  }
}

For now I am doing it that way : 现在,我正在这样做:

Select Aut.name, Aut.age, Book.name AS Book_name, Book.pub_date 
FROM authors AS Aut 
LEFT JOIN books AS Book ON (Aut.id=Book.author_id) 
WHERE Aut.name="Tolkien" 
ORDER BY Book.pub_date DESC 
LIMIT 1 

This means that I have to process the result and then order it to have the json that I showed previously. 这意味着我必须处理结果,然后将其排序为具有我先前显示的json。

Only way is post-processing, but is not so much if you use json_encode for serializing an object: 唯一的方法是后处理,但是如果您使用json_encode序列化对象,则没有那么多:

$res = mysqli_query("SELECT ...");
$obj = new stdClass();
if($row = mysqli_fetch_object($res)) {
    $obj->name=$row->name;
    $obj->age=$row->age;
    $book = new stdClass();
    $book->name = $row->Book_name;
    $book->pub_date = $row->pub_date;
    $obj->last_book = $book;
}

print json_encode($obj);

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM