[英]sympy: substitute function into expression
I have a 2D curve rho(t) 我有2D曲线rho(t)
import sympy as sy
t = sy.Symbol('t', is_real=True) # curve parameter
rho_x = sy.Function('rho_x', is_real=True)(t)
rho_y = sy.Function('rho_y', is_real=True)(t) # components
rho = sy.Matrix([rho_x, rho_y]) # curve vector
tau = rho.diff() / rho.diff().norm() # tangent
after that I want to evaluate parameters of the curve for a specific realization: 之后,我想评估曲线的参数以实现特定的实现:
real_shape = {rho_x: sy.sin(t), rho_y: sy.cos(t)}
f1 = tau.subs(real_shape)
print f1
f2 = sy.lambdify(t, f1)
print f2(0.1)
I found that SymPy does not evaluate the derivatives of sine and cosine functions automatically, and after calling print f2(0.1)
it shows error message: 我发现SymPy不会自动评估正弦和余弦函数的导数,并且在调用
print f2(0.1)
会显示错误消息:
NameError: global name 'Derivative' is not defined
NameError:未定义全局名称“衍生”
What is wrong in my example? 我的例子有什么问题?
You can call doit()
on the Matrix to evaluate it. 您可以在矩阵上调用
doit()
进行评估。
In [49]: f1 = f1.doit()
In [50]: f2 = lambdify(t, f1)
In [51]: print f2(0.1)
[[ 0.99500417]
[-0.09983342]]
Also note that you are putting assumptions wrong way. 还要注意,您以错误的方式进行了假设。 Real assumption on
t
should be put like this: 关于
t
真实假设应如下所示:
In [52]: t = Symbol('t', real=True)
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