[英]setTimeout not working with node.js
I am writing mocha test cases to test the following steps. 我正在编写mocha测试用例来测试以下步骤。 I intend to make an API call and wait for 30 minutes before calling another API.
我打算在调用另一个API之前进行API调用并等待30分钟。 I am using an internal node API which was written to call REST APIs to write this test case.
我正在使用内部节点API编写调用REST API来编写此测试用例。 But for some reason,
setTimeout
is not waiting for the given ms. 但由于某种原因,
setTimeout
不等待给定的ms。 Can someone please help me? 有人可以帮帮我吗?
describe('Checkout - ', function() {
before(function() {
lapetus = test.Lapetus;
});
it('Get purchase contract after session is expired [C123]', function(done) {
this.timeout(180000000);
lapetus.run(function() {
// create customer
......
// create new cart and add one item
......
// create new contract with empty cart id
.......
var pc_id =....;
// wait for 30 minutes for the session to expire
console.log('wait... ' + new Date);
this.setTimeout(getPC(lapetus,pc_id), 18000000);
console.log('ok... ' + new Date);
done();
});
});
var getPC = function(lapetus, pc_id){
// get newly created purchase contract and verify session expired message throws
.....
......
};
});
It does not wait 30 minutes. 它不会等待30分钟。 The call back I put in (the
getPC
method) executes immediately. 我放入的
getPC
( getPC
方法)立即执行。
Any help is appreciated. 任何帮助表示赞赏。
Thanks 谢谢
Your call back is executing immediately because you're calling it then and there. 你的回叫是立即执行的,因为你正在那里召唤它。
Change it to this.setTimeout(function() { getPC(lapetus,pc_id); }, 18000000);
将其更改为
this.setTimeout(function() { getPC(lapetus,pc_id); }, 18000000);
so that what you want to execute is in a function for setTimeout
to call. 所以你想要执行的是在
setTimeout
调用的函数中。
** Edit ** ** 编辑 **
In relation to my last comment. 关于我的上一次评论。 You should move your "ok..." inside of the function you've put inside of
setTimeout
. 你应该在你放入
setTimeout
的函数里面移动你的“ok ...”。 This will cause the "ok..." to execute right before getPC
is called. 这将导致在调用
getPC
之前执行“ok ...”。
this.setTimeout(function() {
console.log('ok... ' + new Date);
getPC(lapetus,pc_id)
}, 18000000);
It is important to understand that setTimeout
will only start a timer which will execute your code later. 重要的是要理解
setTimeout
只会启动一个稍后将执行代码的计时器。 setTimeout
is going to start that timer, and not wait for it to finish. setTimeout
将启动该计时器,而不是等待它完成。 It will move to the next bit of code once it is done starting that timer. 一旦启动该计时器,它将移动到下一位代码。
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