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僵尸浏览器在调用open函数后不会打开一个窗口

[英]zombie browser won't open a window after calling open function

tools 工具

attempt 1 尝试1

  • Darwin 14.3.0 Darwin Kernel Version 14.3.0 达尔文14.3.0 Darwin内核版本14.3.0
  • io.js v1.8.1 io.js v1.8.1
  • zombie Version 4.0.7 2015-04-10 僵尸版本4.0.7 2015-04-10

attempt 2 尝试2

  • Linux ubuntuG5 3.13.0-48-powerpc64-smp Linux ubuntuG5 3.13.0-48-powerpc64-smp
  • node.js v0.10.38 node.js v0.10.38
  • zombie Version 3.1.0 2015-03-15 zombie Version 3.1.0 2015-03-15

commands: 命令:

const Browser = require('zombie');
var url = 'https://google.com'
var browser = new Browser();
browser.open(url=url)
browser.open('http://google.com', function(err) { browser.assert.success();
});
browser.assert.text('title', 'Google');

Results on both machines minus filepath differences: 两台机器上的结果减去文件路径差异:

    assert.js:93
  throw new assert.AssertionError({
        ^
AssertionError: No open window with an HTML document
    at Browser.queryAll (/home/dmmmd/Dropbox/node_js_projects/node_modules/zombie/lib/index.js:432:5)
    at Assert.text (/home/dmmmd/Dropbox/node_js_projects/node_modules/zombie/lib/assert.js:307:33)
    at Object.<anonymous> (/home/dmmmd/Dropbox/node_js_projects/affinity-zombie/sample_zombie.js:7:16)
    at Module._compile (module.js:456:26)
    at Object.Module._extensions..js (module.js:474:10)
    at Module.load (module.js:356:32)
    at Function.Module._load (module.js:312:12)
    at Function.Module.runMain (module.js:497:10)
    at startup (node.js:119:16)
    at node.js:935:3

What am I missing after reading the docs at zombie browser ? zombie浏览器上阅读文档后,我错过了什么? Thanks in advance. 提前致谢。

I tried some other urls, too, even localhost ones without any success. 我尝试了其他一些网址,甚至是localhost也没有成功。

JavaScript, node.js, io.js, and zombie are all new to me so I am basically just following recipes from the documentation and stackoverflow questions. JavaScript,node.js,io.js和zombie对我来说都是新手,所以我基本上只是遵循文档和stackoverflow问题的方法。 I would appreciate any suggestions. 我将不胜感激任何建议。 I suspect I am missing something very simple. 我怀疑我错过了一些非常简单的事情。

This question has been unanswered for a while but I've been working around a similar error message recently. 这个问题暂时没有答案,但我最近一直在处理类似的错误消息。

TL;DR - User browser.visit instead of browser.open() and pass in a callback function to ensure browser's state is populated correctly. TL; DR - 用户browser.visit而不是browser.open()并传入回调函数以确保正确填充浏览器的状态。

You can do this in a number of ways: 您可以通过多种方式执行此操作:

  1. Use the static method Browser.visit() 使用静态方法Browser.visit()
const Browser = require('zombie');
var url = 'https://stackoverflow.com'
Browser.visit(url, function(error, browser) {
    browser.assert.text('title', 'Stack Overflow');
});
  1. Use the instance method browser.visit() 使用实例方法browser.visit()
const Browser = require('zombie');
var url = 'https://stackoverflow.com'
var browser = new Browser();
browser.visit(url, function() {
    browser.assert.text('title', 'Stack Overflow');
});
  1. Use the promise returned by browser.visit() 使用browser.visit()返回的保证
const Browser = require('zombie');
var url = 'https://stackoverflow.com'
var browser = new Browser();
browser.visit(url).then(function() {
    browser.assert.text('title', 'Stack Overflow');
});
  1. If you want to reuse the browser object after the visit, pass a no-op callback to browser.visit() to ensure the browser's state is populated. 如果要在访问后重用浏览器对象,请将无操作回调传递给browser.visit()以确保填充浏览器的状态。
const Browser = require('zombie');
var url = 'https://stackoverflow.com'
var browser = new Browser();
browser.visit(url, function(){}); // NB: no-op callback!
browser.assert.text('title', 'Stack Overflow');

The browser.open() method opens a new browser tab and takes a JavaScript Object containing an url property, so your original code had a syntax error, the line browser.open()方法打开一个新的浏览器选项卡,并获取一个包含url属性的JavaScript对象,因此原始代码有一个语法错误,该行

browser.open(url=url)

should read 应该读

browser.open({url: url})

but it's not clear whether the open method actually makes the new tab visit the url - at least not from a cursory read over the source. 但目前尚不清楚open方法是否实际上使新标签访问了网址 - 至少不是粗略阅读来源。 Use browser.visit() to be on the safe side. 使用browser.visit()是安全的。

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