查找字符串并替换为sed

Question

This contains the following information in a file.

17:06:31.301 [blabal] DEBUG blablabla1
17:06:31.302 [blabal] DEBUG blablabla2
17:06:31.303 [blabal] DEBUG blablabla3

Fetching the contents of that file cat to wonder whether I would like to change it to json format.

[{"time" : "17:06:31.301", "log" : "[blabal] DEBUG blablabla1"}
{"time" : "17:06:31.302", "log" : "[blabal] DEBUG blablabla2"}
{"time" : "17:06:31.303", "log" : "[blabal] DEBUG blablabla3"}]

Is it possible in this way?

Answer 1

$ sed -r 's/^([^ ]+) (.*)/{"time" : "\1", "log" : "\2"}/; 1s/^/[/; $s/$/]/' file 
[{"time" : "17:06:31.301", "log" : "[blabal] DEBUG blablabla1"}
{"time" : "17:06:31.302", "log" : "[blabal] DEBUG blablabla2"}
{"time" : "17:06:31.303", "log" : "[blabal] DEBUG blablabla3"}]

How it works

• sed -r

  Start sed with extended regular expressions. For BSD sed, use -E in place of -r .

• s/^([^ ]+) (.*)/{"time" : "\\1", "log" : "\\2"}/

  Divide the line up into the first word, denoted \\1 , and all the rest, denoted \\2 and then put it into json form.

• 1 s/^/[/

  On the first line, prepend everything with an opening square bracket [ .

• $ s/$/]/

  On the final line (denoted $ ), locate the end of the line, also denoted by $ , and put a closing square bracket ] there.