Whatsapp URL方案不允许iOS中的查询参数

Question

I am not able to share any link which has query parameters like second one.

whatsapp://send?abid=2&text=http://www.google.com WORKS FINE

whatsapp://send?abid=2&text=http://www.google.com/?search=123 DOES NOT WORK

Answer 1

You cannot use the ? for sending any parameter after the first one.

To pass the value of the search as 123 try using &search=123 rather than ?search=123 .

If the http://www.google.com/?search=123 is a whole string then you have to encode it as that contains "?" , "/" and ":".

Your text value would be like this:

whatsapp://send?abid=2&text=http%3A%2F%2Fwww.google.com%2F%3Fsearch%3D123

which is the encoded string of the above. Maybe this could solve your problem.