在C中使用硬编码值创建字符串数组

Question

I have created the array of string with hard-coded values as below :

char dev_string[3][3][15] = {{"item01","item02","item03"},
                                 {"item11","item12","item13"},
                                 {"item21","item22","item23"},
                      };

int main()
{

   printf("string 00 = %s \n",dev_string[0][0]);
   printf("string 01 = %s \n",dev_string[0][1]);
   printf("string 02 = %s \n",dev_string[0][2]);


   printf("string 10 = %s \n",dev_string[1][0]);
   printf("string 11 = %s \n",dev_string[1][1]);
   printf("string 22 = %s \n",dev_string[1][2]);


   printf("string 20 = %s \n",dev_string[2][0]);
   printf("string 21 = %s \n",dev_string[2][1]);
   printf("string 22 = %s \n",dev_string[2][2]);

    return 0;
}

Aim is to create a dictionary in C at the end.Instead of hard-coding i want a pointer based implementation because in future I have to keep adding the items to this string. More over I want to access these strings using some index, which I think I can by providing the row number(0,1 or 2). I am not getting the right way to do it with pointers.What will be other convenient way to do it with pointers ( single or pointer to two dimension?)

Answer 1

char (*sensor_string)[3][3];

for (int i=0; i < 3; ++i) {
    for (int j=0; j < 3; ++j) {
        sensor_string[i][j] = malloc(sizeof(*sensor_string[i][j]) * (strlen("item") + 3));
        strcpy(sensor_string[i][j], "item");
        char* num = malloc(sizeof(*num) * 3);
        sprintf(num, "%d", (i*3 + j + 1));
        strcat(sensor_string[i][j], num);
    }
}