AsyncSocket：始终监听传入的TCP消息

Question

I would like to have a service which connects via TCP to a server and then continuously listens to incoming data. I'm using CocoaAsyncSocket which I'm using in the following way:

self.socket = [[GCDAsyncSocket alloc] initWithDelegate:self delegateQueue:dispatch_get_main_queue()];
NSError *err = nil;
if (![self.socket connectToHost:@"..." onPort:... error:&err]) {
    return;
}

[self.socket readDataWithTimeout:-1 tag:1];

and then in the reading delegate method:

- (void)socket:(GCDAsyncSocket *)sock didReadData:(NSData *)data withTag:(long)tag {
    NSLog(@"%@", data);
    [self.socket readDataWithTimeout:-1 tag:1];
}

is this correct that I'm immediately calling readDataWithTimout:tag: again? Or is there a (better) way to always listen to incoming messages?

Answer 1

For what you are doing this is fine. You need to call -[readDataWithTimeout] in -didReadData, because otherwise you would only receive the first message from the server. GCDAsyncSocket is designed this way, because there are a few other ways you can receive incoming data.