Cypher-收集不同匹配子句之间的关系

Question

I would like to collect relationships from different match clauses as a single column in the results. To be more specific, I have created an example that corresponds to my use case and can be found here: http://console.neo4j.org/r/3g84gc . r1, r2 and r3 are relationships from different match clauses. There is only one valuation of target where multiple relationships are returned:

target = (0:Crew {name:"Neo"}), 
r1 = (0)-[0:KNOWS]->(1), 
r2 = (0)-[1:LOVES]->(2), 
r3 = (1)-[2:KNOWS]->(2). 

What I want is:

target = (0:Crew {name:"Neo"}), 
rels = (0)-[0:KNOWS]->(1), (0)-[1:LOVES]->(2), (1)-[2:KNOWS]->(2)

I would like to do this WITHOUT having to specify all relationships in the return clause and then manually parse relationship columns. It would also be favourable to order valuations of target by the number of relationships found.

Is there a way to do this in Cypher?

Answer 1

If I'm understanding the problem correctly, I think the following RETURN would give you what you want:

RETURN DISTINCT target, [r1,r2,r3]

In the console example that you shared, this returns null values for the second and third positions of the array, but you can fix that, if you want, by changing the OPTIONAL MATCH clauses to MATCH