jQuery：防止孩子继承父级的属性？
[英]jQuery: Prevent child from inheriting the parent's attributes?
问题描述
With jQuery: How do I prevent the children ( <span> ) from inheriting the parents' ( <p> ) attributes? 
使用jQuery：如何防止子级（ <span> ）继承父级（ <p> ）属性？ I've been working on and researching this for 2+ hours; 我一直在研究2个小时以上； nothing has worked. 没有任何效果。
Problem section: 问题部分：
$("p").not("span").css("cursor", "pointer");
<p>...<span>...</span></p>
Full code: 完整代码：
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>
<style>body {font-family:Arial,san-serif;font-size:25pt;}</style>
<body>
<p>Always shown | <span>Show/Hide</span></p>
<p>Always shown | <span>Show/Hide</span></p>
</body>
<script>
//Change pointer to a hand:
$("p").not("span").css("cursor", "pointer");
//Show & Hide by clicking on "Always shown":
function handler(event) {
var target = $(event.target);
if (target.is("p")) {
target.children().toggle();
}
}
$("body").click(handler).find("span").hide();
</script>
4 个解决方案
解决方案1
2 已采纳 2015-04-24 22:13:41
Why don't you use css? 为什么不使用CSS？
p{ cursor: pointer; }
p span{ cursor: default; }
解决方案2
2 2015-04-24 22:16:01
The expression $("p").not("span") literally means "select p elements that are not spans " . 表达$("p").not("span")字面意思是“选择p不在元件spans ”。 Obviously it is always true. 显然，这始终是正确的。
You want to check if p does not contain span children: 您要检查p是否不包含span子代：
$("p:not(:has(span))").css("cursor", "pointer");
However, for this task you should probably go with CSS solution, rather then javascript. 但是，对于此任务，您可能应该使用CSS解决方案，而不是javascript。
解决方案3
1 2015-04-24 22:17:28
解决方案4
1 2015-04-25 00:28:59
You can do this approach also if you want to be done on Jquery : 如果您想在Jquery上完成操作，也可以使用这种方法：
$("p").css("cursor", "pointer");
$("p span").css("cursor", "default");
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