在awk中使用外部变量传递给bash中的ssh

Question

I'm trying to pass an external variable $time to an awk command that im running through an ssh to another machine.

time=...
pastusers=`ssh -n $host "last -n 10 | awk -v TIME=$time '{if ($7 > TIME) print $1}'"`

Is what I've done so far and the command Im passing to ssh works on its own but passing it through ssh causes it to fail.

I also tried..

pastusers=`ssh -n $host "last -n 10"` | awk -v TIME=$time '{if ($7 > TIME) print $1}'

but the ssh call does not return the new lines so awk doesn't get the right information. Anyone have an idea to pass an external variable in what I tried first or how to keep the newline characters from the ssh call in what I tried second?

Answer 1

I have the following test.sh:

#! /bin/bash
host=$1
mytime=$2
pastusers=`ssh -n $host "last -n 10" | awk -v TIME=$mytime '{if($7>TIME) print $1}'`
echo $pastusers

When I run bash test.sh <some_valid_host> 20:00 it prints a list of users as expected, all in the same line. Those being in the same line is also expected.

If you have a file test.txt like:

abc
def ghi

Running

words=`cat test.txt`; echo $words

will print abc def ghi all in same line. This is the expected behavior.