[英]Reversing a word : C++
I want to reverse a char string in c++. 我想在C ++中反转一个char字符串。 I wrote this code: 我写了这段代码:
#include <iostream>
#include <string.h>
using namespace std;
int main(){
char word[80] = "polymorphism";
char rev[80];
int i, j;
int l;
l = strlen(word);
for(i = 0, j = l; i < l-1; i++, j--){
word[j] = rev[i];
}
cout << rev << endl;
return 0;
}
In terminal it shows some characters like this: 在终端中,它显示了一些这样的字符:
83???uH??? ... Something like this
Your character array rev is not zero terminated. 您的字符数组rev不是零终止的。
And istead of to write to rev you are writing to word.:) 而且,您不是在写版本,而是在写单词。:)
word[j] = rev[i];
The loop is also wrong due to condition 由于条件,循环也是错误的
i < l-1;
There must be 必须有
i < l;
The program can look the following way 该程序可以如下所示
#include <iostream>
#include <cstring>
int main()
{
char word[80] = "polymorphism";
char rev[80];
size_t n = std::strlen( word );
size_t i = 0;
for ( ; i < n; i++ ) rev[i] = word[n - i - 1];
rev[i] = '\0';
std::cout << word << std::endl;
std::cout << rev << std::endl;
return 0;
}
The program output is 程序输出为
polymorphism
msihpromylop
Take into account that you can do the same using standard algorithm std::reverse_copy
declared in header <algorithm>
. 考虑到您可以使用标头<algorithm>
声明的标准算法std::reverse_copy
进行相同的操作。 For example 例如
#include <iostream>
#include <cstring>
#include <algorithm>
int main()
{
char word[80] = "polymorphism";
char rev[80];
size_t n = std::strlen( word );
*std::reverse_copy( word, word + n, rev ) = '\0';
std::cout << word << std::endl;
std::cout << rev << std::endl;
return 0;
}
The program output is the same as above 程序输出与上面相同
polymorphism
msihpromylop
#include <iostream>
#include <string.h>
using namespace std;
int main(){
char word[80] = "polymorphism";
char rev[80] = {'\0'};
int i = 0;
int last = strlen(word) - 1;
while(last >= 0) {
rev[i] = word[last];
i++;
last--;
}
cout << rev << endl;
return 0;
}
There are 3 changes I made to your code: 我对您的代码进行了3处更改:
Change 1: Since string length is l
, indexing will be from 0
to l-1
. 更改1:由于字符串长度为l
,因此索引从0
到l-1
。
Change 2: rev
will be storing the values from word
, not the other way round. 变更2: rev
将存储word
的值,而不是相反。
Change 3: A proper string should be \\0
terminated. 更改3:正确的字符串应以\\0
终止。
#include <iostream>
#include <string.h>
using namespace std;
int main(){
char word[80] = "polymorphism";
char rev[80]="";
int i, j;
int l;
l = strlen(word);
for(i = 0, j = l-1; i < l; i++, j--){ //change 1
rev[i] = word[j]; // change 2
}
rev[i]='\0'; // change 3
cout<<rev;
return 0;
}
Working ideone link: http://ideone.com/kIqeNF 可用的ideone链接: http ://ideone.com/kIqeNF
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