Matlab中矩阵向量的排列

Question

I have a static matrix from a file:

    size(data)=[80 5]

What I want is to change position of each vector randomly when I use perms like:

    N = size(data, 1);
    X = perms(1:N);                    % # Permutations of column indices
    Y = meshgrid(1:N, 1:factorial(N)); % # Row indices
    idx = (X - 1) * N + Y;             % # Convert to linear indexing
    C = data(idx) 

But its giving me an error: Maximum variable size allowed by the program is exceeded. Is there any other function to give me what I need?

Answer 1

perms is not good for large numbers ie any number >10

Refer the Documentation

It says

perms(v) is practical when length(v) is less than about 10.

See the size it takes from the following code:

MB(10,1) = 0;
for N = 1:10
    X = perms(1:N);
    dt=whos('X');
    MB(N)=dt.bytes*9.53674e-7;
end

plot(1:10,MB,'r*-');

Note the sudden rise in the steepness of the curve beyond 9.

Answer 2

So i think im done

 N = size(data, 1);
 r=randperm(N);
 for ii=1:80
   matrix(r(ii),:) =data(ii,:)  ;     
 end