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在83年和4个月内转换1000个月

[英]Convert 1000 months in 83 years and 4 months

I try to make something and its work, but when I try to make a date under 1 month its crash. 我尝试做某事及其工作,但是当我尝试在1个月以下约会时,它就会崩溃。 Can someone help me? 有人能帮我吗? The code is like this: 代码是这样的:

int page = int.Parse(Console.ReadLine());
int campingDays = int.Parse(Console.ReadLine());
int pagesPerDay = int.Parse(Console.ReadLine());

int months = page / ((30 - campingDays) * pagesPerDay);
int years = months / 12;
int remainingMonths = months % 12;

Console.WriteLine("{0} years {1} months", years, remainingMonths);

That's how i solve the "0 years 1 months" problem. 这就是我解决“ 0年1个月”问题的方式。 There you go! 你去!

    int readedPages = (30 - campingDays) * regularDays;

    if ((campingDays == 30) || (regularDays == 0))
    {
        Console.WriteLine("never");
    }
    else
    {
        double readDuration = Math.Ceiling(bookPages / (double)readedPages);
        double years = (int)(readDuration / 12);
        double remainingMonths =(readDuration % 12);
        Console.WriteLine("{0} years {1} months", years, remainingMonths);
    }

You would get divide by zero error whenever 每当你会得到除以零的错误

  • campingDays is 30 because of (30 - campingDays) campingDays是30,因为(30 - campingDays)
  • pagesPerDay is - 0 pagesPerDay是-0

The problematic line: 有问题的行:

int months = page / ((30 - campingDays) * pagesPerDay);

You may want 2 if statements to handle those cases. 您可能需要2条if语句来处理这些情况。

Michal Ciechan is correct. Michal Ciechan是正确的。 (Just read your answer closely) (请仔细阅读您的答案)

suggestion: 建议:

int _campingDaysAdj = 30 - campingDays;
if(_campingDaysAdj > 0 && pagesPerDay > 0)
{
    int months = page / ((30 - campingDays) * pagesPerDay);
    int years = months / 12;
    int remainingMonths = months % 12;

    Console.WriteLine("{0} years {1} months", years, remainingMonths);
}
else
{
    //throw an exception or an error message etc.
}

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