如何从NSString中删除08十六进制字符

Question

I have a long string, and I would like to remove a specific hexadecimal character from it.

NSString * myString = @"longlongstringwithcharacters\"ofallsorts\"";

Any suggestions?

The hex character I am after is 08 , that corresponds to backspace. How can I use code like the following to substitute it? I have no idea on how to represent 08 in a string:

NSString *stringWithoutSpaces = [myString 
   stringByReplacingOccurrencesOfString:@" " withString:@""];

EDIT:

I will try to clarify a bit more what I am trying to do..

I am trying to remove all occurrences of a character that corresponds to 08 hex from the string that I receive as payload.

The payload is in a string format and I found out the character by using Xcode debugger and view the hex codes of the string as there was an invalid character when trying to covert the NSData corresponding to the string to a NSDictionary.

I am not sure how to phrase the problem correctly..

Answer 1

- (NSString *)stringFromHexString:(NSString *)hexString {

    // The hex codes should all be two characters.
    if (([hexString length] % 2) != 0)
        return nil;

    NSMutableString *string = [NSMutableString string];

    for (NSInteger i = 0; i < [hexString length]; i += 2) {

        NSString *hex = [hexString substringWithRange:NSMakeRange(i, 2)];
        NSInteger decimalValue = 0;
        sscanf([hex UTF8String], "%x", &decimalValue);
        [string appendFormat:@"%c", decimalValue];
    }

    return string;
}

Try this code...This will help you to convert Hex to string

Answer 2

NSString * str = @"68656C6C6F";
NSMutableString * newString = [[[NSMutableString alloc] init] autorelease];
int i = 0;
while (i < [str length])
{
    NSString * hexChar = [str substringWithRange: NSMakeRange(i, 2)];
    int value = 0;
    sscanf([hexChar cStringUsingEncoding:NSASCIIStringEncoding], "%x", &value);
    [newString appendFormat:@"%c", (char)value];
    i+=2;
}

this will help u to convert Hex to NSString

Answer 3

This code worked for me:

    NSString * dataString = message.payloadString;
    NSString * wrongCharacter = [[NSString alloc] initWithFormat:@"%c", (char)0x08];
    dataString = [dataString stringByReplacingOccurrencesOfString:wrongCharacter withString:@""];