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在C中订购链表的问题

[英]Problems ordering a linked list in C

I got issues trying to order a linked list from its min to its max, the code is: 我在尝试从最小到最大排序链表时遇到问题,代码是:

struct nodo *orderList (struct nodo *p) {

struct nodo *head=p;
struct nodo *min=p;
int *tmp=NULL;

while (min != NULL) {
    p = min;
    // p = p->succ (not necessary i think)
            while (p != NULL) {
                    if (p->info < min->info) {
                            tmp = &min->info;
                            min->info = p->info;
                            p->info = *tmp;
                    }
                p=p->succ;
            }
        min=min->succ;
}
return head;
}

The output i get (i use a tested function to create a list with n nodes from input) : 我得到的输出(我使用一个经过测试的函数从输入创建具有n个节点的列表):

Number of elements: 4
insert 4 positive numbers: 
4
3
2
1

1 ->  1 ->  1 ->  1 -> 

By using a int * , when you swap the info field, you refer to the modified field. 通过使用int * ,当您交换信息字段时,可以引用修改后的字段。

You should declare tmp as: 您应该将tmp声明为:

int tmp;

and adjust your swap code accordingly. 并相应地调整交换代码。

In this way you would copy the value of min->info before changing it. 这样,您可以在更改之前复制 min->info 的值

This code does not swap the data 此代码不交换数据

tmp = &min->info;
min->info = p->info;
p->info = *tmp;

The third line simply moves the data back to where it was, since min->info now contains p->info . 第三行只是将数据移回原来的位置,因为min->info现在包含p->info

You need to swap like this 您需要像这样交换

int tmp = min->info;
min->info = p->info;
p->info = tmp;

assuming the data type is int as you didn't post the struct . 假设数据类型为int因为您没有发布struct

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