如何获取具有可绘制状态的按钮的背景色？

Question

Here is my drawable state:

<?xml version="1.0" encoding="utf-8" ?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
    <item android:state_pressed="true" >
        <shape>
            <solid
                android:color="#ffdcd400" />
        </shape>
    </item>
    <item>
        <shape>
            <solid
                android:color="#ffe8e000" />
        </shape>
    </item>
</selector>

I get the button with this function:

public void ir(View v)
{
        Button boton_clickeado=(Button)v;
        StateListDrawable drawable= (StateListDrawable) v.getBackground();
}

I want to get the background color (state not pressed) "#ffe8e000" programmatically. But I don't know which function use to obtain it.

Answer 1

尝试这个 ..

int color = Color.TRANSPARENT; StateListDrawable drawable= (StateListDrawable) v.getBackground(); if (drawable instanceof ColorDrawable) color = ((ColorDrawable) drawable).getColor();