[英]How to display a graph of top n items?
I have a list of events and want to show who are the top participants (the ones that have come more often) 我有一个活动列表,并想显示谁是最重要的参与者(经常参加的人)
What I've done is a rowChart 我所做的是一个行图
var dim = ndx.dimension (function(d) {
if (!d.guest) {
return "Not mentioned";
}
return d.guest;
});
var group = dim.group().reduceSum(function(d) { return 1; });
var graph = dc.rowChart (".topvisitor")
.margins({top: 0, right: 10, bottom: 20, left: 10})
.height(300)
.width(200)
.cap(10)
.x(d3.scale.ordinal())
.elasticX(true)
.ordering(function(d){return -d.value})
.dimension(dim)
.group(group);
That kind of works, but there is a big "other" that I'd want to remove. 这种工作,但是我想删除一个很大的“其他”。 Am I abusing the rowChart to create a topN graph? 我是否在滥用rowChart创建topN图?
So the path I followed is to filter the data first (by creating a fake group that has a new all() function that returns a top(n) of the real group): 因此,我遵循的路径是首先过滤数据(通过创建一个伪造的组,该组具有一个新的all()函数,该函数返回真实组的top(n)):
var group = dim.group().reduceSum(function(d) { return 1; }); var group = dim.group()。reduceSum(function(d){return 1;});
var filteredGroup = (function (source_group) {return {
all:function () {
return source_group.top(10).filter(function(d) {
return d.key != "Not mentioned";
});
}
};})(group);
and for the graph, use this group 对于图表,请使用该组
.group(filteredGroup); 。集团(filteredGroup);
I think it does the trick, despite Gordon's approval, still feels a bit hackish, but it does the job (cap+filter some data) 我认为,尽管获得了戈登的认可,它还是可以解决问题的,但确实可以完成工作(使用Cap +过滤某些数据)
you have to remove the cap, or implement the top function (same as all in this case) 您必须卸下盖子或实现顶部功能(与本例中的所有功能相同)
As a side note: rowChart seems to be one of the chart where you can override the data function, so: 附带说明:rowChart似乎是您可以覆盖数据功能的图表之一,因此:
.data(function (group) {
return group.top(10);
})
would Work too (but wouldn't filter the "Not mentioned" items 也可以使用(但不会过滤“未提及”的项目
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