简体   繁体   English

递归插入双向链表的末尾

[英]Recursively insert at the end of doubly linked list

I have a doubly linked list, and I want to insert an element at the end of the list recursively. 我有一个双向链表,我想递归地在列表末尾插入一个元素。 I have a method now that does this without recursion, and it works. 我现在有一个方法可以做到这一点而无需递归,并且可以正常工作。 I just can't seem to understand how to do it with recursion. 我似乎无法理解如何使用递归。 Inserting at the end of a singly linked list with recursion is quite easy to understand I think, so I hope that someone can explain how to it do it when the list is doubly linked. 我认为,在带有递归的单链接列表的末尾插入是很容易理解的,因此,我希望有人可以解释在双链接列表时如何执行此操作。 Here is my normal insertion method that I want to make recursive: 这是我要递归的普通插入方法:

public void insert(T element) {
    Node in = new Node(element);

    if (in == null) {
        first = in;
    } else {
        Node tmp = first;
        while (tmp.next != null) {
            tmp = tmp.next;
        }
        tmp.next = in;
        in.prec = tmp;
    }
}

The idea is just to re-write the while loop with a function call: 这个想法只是用一个函数调用来重写while循环:

public void insert(T element) {
    insert(element, first);    // initialization
}

private void insert(T e, Node n) {
    if(n == null) {            // if the list is empty
        first = new Node(e);
    } else if(n.next == null) {       // same condition as in the while loop
        None newNode = new Node(e);
        n.next = newNode;
        newNode.prec = n;
    } else {
        insert(e, n.next);    // looping
    }
}

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM