从多个同时打开的文件行中删除“ \\ n”

Question

I need to open a small but variable number of files, each of which has the same number of lines. I then need to return a tuple of the lines in each. My code returns a tuple, but each element retains its '\\n'; how to strip this before it gets packed into the tuple?

this is the code so far

files = ['file1', 'file2', 'file3']
fds = [ open(file) for file in files ] # gets all file open at same time
read_fds = izip( *fds )
for tpl in read_fds:
    print tpl    # will become a 'yield' stmt once the '\n' is sorted
for fd in fds:
    fd.close()

I have a test set of 3 files, each with 5 lines, each which indicates file number line number. The code prints this accurate record of these test files.

('f1ln1\n', 'f2ln1\n', 'f3ln1\tthis\tthat\n')
('f1ln2\n', 'f2ln2\n', 'f3ln2\tthis\tthat\n')
('f1ln3\n', 'f2ln3\n', 'f3ln3\tthis\tthat\n')
('f1ln4\n', 'f2ln4\n', 'f3ln4\tthis\tthat\n')
('f1ln5\n', 'f2ln5\n', 'f3ln5\tthis\tthat\n')

So far so good, but how to strip() that '\\n' from each line before it gets packed into the tuple?

I know there's an answer out there! Looking fwd to suggestions. Thank you & have a great day.

Answer 1

You can also use slicing of the string

for tpl in read_fds:
    list_stripped = []
    for s in tpl:
        list_stripped.append(s[:-1])
    print tuple(list_stripped)

Answer 2

How about:

for tpl in read_fds:
    templist = []
    for item in tpl:
        templist.append(item.rstrip("\n"))
    print tuple(templist)

This will remove any newline character on the right side of the string

Answer 3

I think the easiest way would be to modify the assignment to read_fds so that it generates modified tuples from izip :

read_fds = (tuple(s.rstrip() for s in tup) for tup in izip(*fds))

However, I have not tested this.