我如何解构匹配语法:: ptr :: P？

Question

I have a function which tries to match an syntax::ast::ExprBinary(syntax::ast::BinOp, syntax::ptr::P<ast::Expr>, syntax::ptr::P<syntax::ast::Expr>) , but I cannot find the right syntax to match the P so I get the contained expression out of it. I see that I can use Deref to get at the Expr , but this is cumbersome.

Is there a way to get rid of the P within the match (or if let ) clause?

Answer 1

There's no way to pattern match through a P : the field is private and we don't have generalised pointer pattern matching (yet).

The only ways to get at the contained data are Deref (for a & ), and the methods and_then and map (for by-value).