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在bash文件中执行python文件并读取两个文本文件

[英]Execute a python file in a bash file and read two text file

I have a python file which works fine. 我有一个工作正常的python文件。 It takes a file and does something on it. 它需要一个文件并对其执行某些操作。 So I run it like this: 所以我这样运行:

./MyPy.py File.txt ./MyPy.py File.txt

Then with bash script I grep some part of it. 然后,使用bash脚本,我将其部分复制。

./MyPy.py File.txt | ./MyPy.py File.txt | grep -vE "^color" grep -vE“ ^ color”

So what I want to do is creating a bash file which asks the user for the path of the File and does ./MyPy.py File.txt | 因此,我想做的是创建一个bash文件,该文件要求用户提供文件的路径并执行./MyPy.py File.txt | grep -vE "^color" in it and gives the result to out put. grep -vE“ ^ color”放入其中,并将结果输出。

Can you please help me with this ? 你能帮我吗?

This should work: 这应该工作:

#!/bin/bash
read -e -p "Enter the path of the file: " file
./MyPy.py "$file" | grep -vE "^color"

Additional improvement: 其他改进:

If you want to interpret ~ as /home/user ie use ~/Downloads to point to /home/user/Downloads , then: 如果你想诠释~/home/user即使用~/Downloads指向/home/user/Downloads ,那么:

#!/bin/bash
read -e -p "Enter the path of the file: " file
file=${file/#\~/$HOME}
./MyPy.py "$file" | grep -vE "^color"

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