原始int值转换？

Question

public class Test3 {

    public static void main(String[] args) {
        int i = 010;
        System.out.println(i); // prints 8          
    }

}

How come it prints 8? How is it getting converted? Debugging the program didn't help.

Answer 1

010 is parsed as an octal number (as any number literal starting with 0 ). Its decimal value is 8. System.out.println prints the decimal value.

Answer 2

Any number of digits, optionally preceded by a sign (+ or -). Decimal digits assumed by default (0-9), but a 0 prefix introduces octal digits (0-7), and > 0x hexadecimal digits (0-f).

Since you prefixed 10 with a 0 then it's read as an octal rather than decimal.

Converting octal to decimal in Java:

String octal = "010";
int decimal = Integer.parseInt(octal, 10);

System.out.println(decimal);

Output:

10

Answer 3

这是八进制到十进制的转换。有关更多信息，请访问： http : //www.buzzle.com/articles/octal-to-decimal-how-to-convert.html