将mysql查询逻辑转换为Laravel查询生成器

Question

I am trying to convert my mysql query logic to Laravel query builder. II have no Idea how to convert it as laravel query.

my query logic is

SELECT id,name,
case 
    when visibility_status = '1' 
    then 'Visible' 
    when visibility_status = '0' 
    then 'Invisible'
    end as visibility_status FROM `flowers`

generally I write a select query using query builder but cant implement above logic

$result = DB::table('flowers')
        ->select('flowers.id as id', 'flowers.name as name',
'flowers.visibility_status as visibility_status');

Answer 1

Try This

$users = DB::table('flowers')
->select(["id", "name",
      DB::raw("
       case 
          when visibility_status = '1' 
          then 'Visible' 
          when visibility_status = '0' 
          then 'Invisible'
          end as visibility_status
    ")])->get();

Here is the reference for it http://laravel.com/docs/4.2/queries#raw-expressions