Nunit断言的条件

Question

I need to compare two List s by NUnit's Assert.AreEqual . If this statement is false (lists not the same) - then I need find elements in lists which not the same.

How I can use If statement for know- Assert return true or false ?

Answer 1

It seems that nunit CollectionAssert.AreEquivalent is exactly what you were looking for.

This method compare between the collections. If a mismatch was found then the method will throw exception with the difference.

Answer 2

Here's a possible solution.

    [Test]
    public void TestMethod1()
    {
        List<int> a = new List<int>();
        List<int> b = new List<int>();

        //Fake data              
        a.Add(1);
        b.Add(2);
        b.Add(2);

        Assert.IsTrue(AreEquals(a,b), GetDifferentElements(a,b));
    }

    private string GetDifferentElements(List<int> a, List<int> b)
    {

        if (AreEquals(a, b))
        {
            return string.Empty;
        }
        if (a.Count != b.Count)
        {
            return "The two lists have a different length";
        }
        StringBuilder s = new StringBuilder();
        for (int i = 0; i < a.Count; i++)
        {
            if (a[i] != b[i])
            {
                s.Append(i.ToString() + " ");
            }
        }
        return string.Format("Elements at indexes {0} are different", s.ToString());
    }

    private bool AreEquals(List<int> a, List<int> b)
    {
        if (a.Count != b.Count)
        {
            return false;
        }
        for (int i = 0; i < a.Count; i++)
        {
            if (a[i] != b[i])
            {
                return false;
            }
        }
        return true;
    }

UPDATE

Of course I was unaware of the CollectionAssert.AreEquivalent method provided in the accepted answer. That's a better solution of course!