OS X Shell脚本可执行文件不起作用

Question

I have a shell script that I'm trying to make executable.

Here's the script: (it doesn't do anything useful yet. just trying to get it to run properly)

#!/bin/sh

function rip_it_good(){
    echo "function called"
}

rip_it_good

First I made it executable:

$ chmod +x ripitgood.sh

So far, so good. If I run it from terminal in the local directory

$ ./ripitgood.sh

it runs just fine and I get the proper output of "function called".

Next I linked to it from /usr/local/bin

$ sudo ln -s ripitgood.sh /usr/local/bin/ripitgood

But if I try to run it using the newly created link:

$ ripitgood

I get an error

"-bash: ripitgood: command not found"

I checked, and yes /usr/local/bin is in my PATH

$ echo $PATH
/usr/local/bin:/usr/bin:/bin:/usr/sbin

And I tried to run it directly

$ /usr/local/bin/ripitgood
-bash: /usr/local/bin/ripitgood: No such file or directory

So, I opened up finder and checked, and yes, the link "ripitgood" exist in the /usr/local/bin directory

I can still run it from the directory where it resides:

./ripitgood.sh
function called

What am I missing?

Answer 1

The problem is in how you create the symlink:

sudo ln -s ripitgood.sh /usr/local/bin/ripitgood

The symlink will literally be ripitgood.sh , but there is no ripitgood.sh in /usr/local/bin . Try creating the symlink like this:

sudo ln -s $(pwd)/ripitgood.sh /usr/local/bin/ripitgood

That will use the full, absolute path to ripitgood.sh in the symlink.