[英]How to call static method provided by protocol in Swift
How to access to static
protocol method within a instance如何访问实例内的static
协议方法
I have a list of Contact
, the contact can be a FamilyContact
that inherit from Contact
and the GroupStatus protocol
我有一个列表Contact
,联系人可以是FamilyContact
从继承Contact
和GroupStatus protocol
I want to call the static method from GroupStatus
but in vain...我想从GroupStatus
调用静态方法但徒劳无功...
Here is my code这是我的代码
protocol GroupStatus {
static func isPrivate() -> Bool // static method that indicates the status
}
protocol IsBusy {
func wizzIt()
}
class AdresseBook {
private var contacts = [Contact]()
func addOne(c: Contact) {
contacts.append(c)
}
func listNonPrivated() -> [Contact]? {
var nonPrivateContact = [Contact]()
for contact in contacts {
// here is I should call the static method provided by the protocol
if self is GroupStatus {
let isPrivate = contact.dynamicType.isPrivate()
if !isPrivate {
nonPrivateContact.append(contact)
}
}
nonPrivateContact.append(contact)
}
return nonPrivateContact
}
}
class Contact : Printable {
var name: String
init(name: String) {
self.name = name
}
func wizz() -> Bool {
if let obj = self as? IsBusy {
obj.wizzIt()
return true
}
return false
}
var description: String {
return self.name
}
}
class FamilyContact: Contact, GroupStatus {
static func isPrivate() -> Bool {
return true
}
}
I can't compile Contact.Type does not have a member named 'isPrivate'
我无法编译Contact.Type does not have a member named 'isPrivate'
How can I call it ?我怎么称呼它? It works if I delete the static
keyword, but I think is more logical to define it static.如果我删除static
关键字,它会起作用,但我认为将其定义为 static 更合乎逻辑。
If I replace如果我更换
let isPrivate = contact.dynamicType.isPrivate()
by经过
let isPrivate = FamilyContact.isPrivate()
It works, but I can have more than 1 subclasses它有效,但我可以有 1 个以上的子类
If I remove the static
keywork I can do it by this way :如果我删除static
键工作,我可以通过这种方式做到这一点:
if let c = contact as? GroupStatus {
if !c.isPrivate() {
nonPrivateContact.append(contact)
}
}
But I want to keep the static
keyword但我想保留static
关键字
This looks like a bug or a non-supported feature.这看起来像是一个错误或不受支持的功能。 I would expect that the following works:我希望以下工作:
if let gsType = contact.dynamicType as? GroupStatus.Type {
if gsType.isPrivate() {
// ...
}
}
However, it does not compile:但是,它不会编译:
error: accessing members of protocol type value 'GroupStatus.Type' is unimplemented
It does compile with FamilyContact.Type
instead of GroupStatus.Type
.它确实使用FamilyContact.Type
而不是GroupStatus.Type
编译。 A similar problem is reported here:这里报告了一个类似的问题:
Making isPrivate()
an instance method instead of a class method is the only workaround that I currently can think of, maybe someone comes with a better solution ...使isPrivate()
成为实例方法而不是类方法是我目前能想到的唯一解决方法,也许有人提出了更好的解决方案......
Update for Swift 2 / Xcode 7: As @Tankista noted below, this has been fixed. Swift 2 / Xcode 7 的更新:正如@Tankista 在下面提到的,这已经得到修复。 The above code compiles and works as expected in Xcode 7 beta 3.上面的代码在 Xcode 7 beta 3 中按预期编译和工作。
type(of: contact).isPrivate()
这应该适用于最近的 Swift。
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