[英]WebTarget from String
I'm consuming a REST API via Jersey-Client. 我正在通过Jersey-Client使用REST API。 The API is paginated.
该API是分页的。
Client client = ClientBuilder.newClient()
.register(HttpAuthenticationFeature.basic(USER_NAME, PASSWORD));
WebTarget target = client.target(HOST).path(API_BASE).path("content");
PageResult pageResult = target.request(JSON).get()readEntity(PageResult.class);
The response looks something like this: 响应看起来像这样:
{
"results":[...
],
"start": 0,
"limit": 25,
"size": 25,
"_links": {
"self": "http://localhost:8090/rest/api/content",
"next": "/rest/api/content?limit=25&start=25",
"base": "http://localhost:8090",
"context": ""
}
}
The pageResult
object is populated correctly with the response. 用响应正确填充了
pageResult
对象。 Now I want to create a new WebTarget
or reuse the current WebTarget
. 现在,我想创建一个新的
WebTarget
或重用当前的WebTarget
。 What has changed are the query parameters. 更改的是查询参数。
What is the easiest way to create the new WebTarget
? 创建新的
WebTarget
的最简单方法是什么?
target = client.target(pageResult._links.base).path(pageResult._links.next);
This way the query parameters are not interpreted correctly. 这样,查询参数将无法正确解释。 I also don't want to parse the url by myself.
我也不想自己解析网址。 What API is there?
有什么API? I could add the query parameters by hand, but I think there should be a method like
WebTarget.fromString(pageResult._links.base + pageResult._links.next)
我可以手动添加查询参数,但我认为应该有一个类似
WebTarget.fromString(pageResult._links.base + pageResult._links.next)
Change the line 换线
target = client.target(pageResult._links.base).path(pageResult._links.next);
to 至
target = client.target(pageResult._links.base + pageResult._links.next)
From the doku 从杜库
/**
* Build a new web resource target.
*
* @param uri web resource URI. May contain template parameters. Must not be {@code null}.
* @return web resource target bound to the provided URI.
* @throws IllegalArgumentException in case the supplied string is not a valid URI template.
* @throws NullPointerException in case the supplied argument is {@code null}.
*/
public WebTarget target(String uri);
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