使用正则表达式过滤并查找字符串中的整数

Question

I have this long string:

String responseData = "fker.phone.bash,0,0,0"
    + "fker.phone.bash,0,0,0"
    + "fker.phone.bash,2,0,0";

What I want to do is to extract the integers in this string. I have successfully done that with this code:

 String pattern = "(\\d+)";
 // this pattern finds EVERY integer. I only want the integers after       the comma

        Pattern pr = Pattern.compile(pattern);

        Matcher match = pr.matcher(responseData);


        while (match.find()) {

            System.out.println(match.group());

        }

So far it is working, but I want to make my regex more secure because the responsedata I get is dynamic. Sometimes I might get an integer in the middle of the string, but I only want the last integers, meaning after the comma.

I know the regex for starts with is ^ and I have to put my comma tecken as an argument, but I don't know how to piece it all together and that is why I am asking for help. Thank you.

Answer 1

String pattern = "(,)(\\d)+";

然后得到第二组。

Answer 2

You can use positive lookbehind for that:

String pattern = "(?<=,)\\d+";

You don't need to extract any groups to do use that solution, because lookbehind is zero-length assertion .

Answer 3

You can simply use the following and find by match.group(1) :

String pattern = ",(\\d+)";

See working demo

You can also use word boundaries to get independent numbers:

String pattern = "\\b(\\d+)\\b";