为Python类实现“和”？

Question

I have code similar to this:

import operator
class Comparator:
     def __init__(self,fieldName,compareToValue,my_operator):
         self.op = my_operator
         self.field = fieldName
         self.comparedTo = compareToValue
     def __call__(self,row):
         my_row_val = getattr(row,self.field)
         return self.op(my_row_val,self.comparedTo)


class Row:
    class RowItem:
         def __init__(self,name):
              self.name = name
         def __eq__(self,other):
             return Comparator(self.name,other,operator.eq)
    val1 = RowItem("val1")
    val2 = RowItem("val2")
    val3 = RowItem("val3")
    val4 = RowItem("val4")
    def __init__(self, val1, val2, val3, val4):
        self.val1 = val1
        self.val2 = val2
        self.val3 = val3
        self.val4 = val4
    def __str__(self):
        return str([self.val1,self.val2,self.val3,self.val4])
    def __repr__(self):
        return str(self)


class MyTable:
    def __init__(self,rows):
        self.rows = rows
    def filter(self,condition):
        for row in self.rows:
            if condition(row):
               yield row

rows = [Row(1,2,3,"hello"),Row(1,2,7,"cat"),Row(1,2,3,"hi"),Row(7,7,7,"foo")]
mytable = MyTable(rows)

I can successfully run filtering tests, for example:

print list(mytable.filter(Row.val3 == 7))
# prints [[1, 2, 7, 'cat'], [7, 7, 7, 'foo']]
print list(mytable.filter(Row.val2 == 2))
# prints [[1, 2, 3, 'hello'], [1, 2, 7, 'cat'], [1, 2, 3, 'hi']]

but when I try to use an and it does not work as I would like:

print list(mytable.filter((Row.val3 == 7) and (Row.val2 == 2)))
# this only evaluates the second condition, instead of both conditions, printing:
# [[1, 2, 3, 'hello'], [1, 2, 7, 'cat'], [1, 2, 3, 'hi']]

How can I get the and to work correctly?

Answer 1

You cannot hook into the and and or logical operators, because they short-circuit ; the left-hand expression is evaluated first and if the result of that expression determines the outcome, the right-hand expression is never evaluated even. The operation returns the value of the last expression evaluated.

In your case, the (Row.val3 == 7) and (Row.val2 == 2) expression evaluates (Row.val3 == 7) first, and as that returns an instance without any specific hooks to say otherwise, it is considered a true value , so the result of the right-hand expression is then returned.

You can use & and | (bitwise AND and OR) operators here, these delegate to the object.__and__ and object.__or__ hooks. This is what ORM libraries like SQLAlchemy do.

The corresponding operator functions are operator.and_ and operator.or_ .