JButton的gridLayout，每个JButton的actionListener

Question

I have a gridLayout of JButtons. I'd like to distinguish every JButton from each other in the actionPerformed function. I don't want to "name" each JButton. The user press a JButton randomly. Is there any method to know which button has been pressed? It is possible?

    [....]
    tUsuariCPU = new JButton[mida][mida];
    for (int i=0;i<size;i++){
        for (int j=0;j<size;j++){
            JButton temp = new JButton();
            tUsuariCPU[i][j] = temp; 
            temp.addActionListener(this);
            panel.add(temp);
        }
      }
   }

   public void actionPerformed(ActionEvent e) {}
          [....]

   }

Answer 1

If you wish to use a single ActionListener , you can check which Component fired the event by using the getSource button and comparing the instance to the JButton instances. Below uses a loop to loop over the 2D array of JButtons:

public void actionPerformed(ActionEvent e) {}
    for ( int i = 0; i < tUsuariCPU.length; i++ ){
        for ( int j = 0; j < tUsuariCPU[i].length; j++ ){
            if ( e.getSource() == tUsuariCPU[i][j] ){
                //do something
            }
        }
    }
}

Alternatively, you can add a single ActionListener per button, or set the ActionCommand of the JButton and use this value to determine which JButton fired the event ( e.getActionCommand().equals(myButton.getActionCommand()) )