[英]c# Main Class include “subclass”
Hey I have two classes 嘿我有两节课
class Main
{
public exLog exLog;
public Main()
{
}
}
and 和
class exLog
{
public exLog()
{
}
public exLog(String where)
{
}
public exLog(String where, String message)
{
}
}
i tried to call exLog direct without giving exLog a parameter. 我试图直接给exLog打电话而不给exLog一个参数。 So I can call any class with the Main Method.
因此,我可以使用Main方法调用任何类。 How should I do that?
我应该怎么做?
public String ReadFileString(String fileType, String fileSaveLocation)
{
try
{
return "";
}
catch (Exception)
{
newMain.exLog("", "");
return null;
}
}
I like to call them like a funtion in Main 我喜欢称它们为Main中的功能
You can call it as soon as you instantiate it. 您可以在实例化它后立即调用它。
public Main()
{
exLog = new exLog();
exLog.MethodInClass();
}
Also, if you are not in the same assembly you'll need to make exLog public. 另外,如果您不在同一程序集中,则需要将exLog公开。
Finally, this is C# and the style dictates that class names should be PascalCased. 最后,这是C#,样式指示类名称应为PascalCased。 It's a good habit to form.
这是养成的好习惯。
I think you're confused about classes, instances, constructors, and methods. 我认为您对类,实例,构造函数和方法感到困惑。 This does not work:
这不起作用:
newMain.exLog("", "");
because exLog
in this case is a property , not a method . 因为
exLog
在这种情况下是属性 ,而不是方法 。 (It's confusing because you use the same name for the class and the property, which is why most conventions discourage that). (这令人困惑,因为您对类和属性使用了相同的名称,这就是为什么大多数约定不鼓励这样做的原因)。
You can call a method on the instance : 您可以在实例上调用方法 :
newMain.exLog.Log("", "");
but then you'll need to change the names of the methods (and add a return type) in your exLog
class so they don't get interpreted as constructors: 但是然后您需要在
exLog
类中更改方法的名称(并添加返回类型),以使它们不会被解释为构造函数:
class exLog
{
public void Log()
{
}
public void Log(String where)
{
}
public void Log(String where, String message)
{
}
}
Methinks you want something like Adapter Pattern Methinks,你想要像适配器模式这样的东西
class Main
{
private exLog exLog;
public Main()
{
}
public void ExLog()
{
exLog = new exLog();
}
public void ExLog(String where)
{
exLog = new exLog(where);
}
public void ExLog(String where, String message)
{
exLog = new exLog(where, message);
}
}
class Main
{
public exLog exLog;
public Main()
{
exLog = new exLog();
exLog.ReadFileString("", "");
}
}
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