Java正则表达式找到第一个字符不在字符范围内

Question

In my SQL Server there is a PATINDEX function. For example:

patindex('%[^A-Z,^a-z,^0-9,^\,^_]%', SqlInstanceName)

This returns the string index position of the first character that is NOT in AZ, NOT in az, NOT in 0-9, NOT = '\\' (backslash) and NOT = '_' (underscore).

I want to do the same in Java 1.6/1.7 using Regex or using any built-in Java library methods.

Answer 1

In Java you can do:

Pattern p = Pattern.compile("[^\\w\\\\]");
Matcher m = p.matcher(input); // input is your String 

if (m.find())
   System.out.println(m.start()); // start position of your match

Answer 2

thanks all! Using above tips I wrote this Java code and it seems to work for me:

// start code fragment
Pattern pattern = Pattern.compile("([a-zA-Z0-9_\\\\]*)");
Matcher matcher = pattern.matcher(inputString);
if (matcher.find()) 
{
    inputString = matcher.group(1);
}
// end code fragment

Much appreciated!