[英]How to add conditional button in template field gridview?
I have one gridview
that contains some fields, I want to show button in TemplateField when Process field has value. 我有一个包含一些字段的
gridview
,我想在Process字段有值时在TemplateField中显示按钮。
Here is my code: 这是我的代码:
<asp:GridView ID="grdList" PageSize="20" runat="server" DataSourceID="ODList" AllowPaging="True"
AllowSorting="True" PagerSettings-Position="Top" AutoGenerateColumns="False"
ShowFooter="True" ShowHeaderWhenEmpty="True" OnPageIndexChanged="grdList_PageIndexChanged">
<Columns>
<asp:BoundField DataField="MeasureCatalogId" SortExpression="MeasureCatalogId" />
<asp:BoundField DataField="MeasureName" SortExpression="MeasureName" />
<asp:TemplateField SortExpression="Process">
<ItemTemplate>
<asp:Label ID="Label2" runat="server" Text='<%# Bind("Process") %>'></asp:Label>
</ItemTemplate>
<EditItemTemplate>
<asp:TextBox ID="TextBox1" runat="server" Text='<%# Bind("LevelId") %>'></asp:TextBox>
</EditItemTemplate>
</asp:TemplateField>
<asp:TemplateField ShowHeader="False">
<ItemTemplate>
<%if(????????) -- want condition for process!= ""
{
%>
<img class="semPopup" sempopupurl='<%=Constant.AppPath %>/forms/baseform/MeasureProcessFromCatalogForm.aspx?t=2&lid=<%# Eval("LevelId") %>&mid=<%# Eval("MeasureCatalogId") %>'
sempopupwidth="<%=width %>" sempopupheight="<%=height %>"
src="../../App_Themes/images/select2.gif" />
<%} %>
</ItemTemplate>
</asp:TemplateField>
</Columns>
<PagerSettings Position="Top"></PagerSettings>
<PagerStyle CssClass="grid_pager" />
</asp:GridView>
As an alternative to the other recommendations; 作为其他建议的替代方案; you could try using a code expression on the field:
你可以尝试在字段上使用代码表达式:
<asp:TemplateField ShowHeader="False">
<ItemTemplate>
<img class="semPopup" sempopupurl='<%=Constant.AppPath %>/forms/baseform/MeasureProcessFromCatalogForm.aspx?t=2&lid=<%# Eval("LevelId") %>&mid=<%# Eval("MeasureCatalogId") %>'
sempopupwidth="<%=width %>" sempopupheight="<%=height %>"
src="../../App_Themes/images/select2.gif" Visible='<%# ShowButton(Eval("Process")) %>'/>
</ItemTemplate>
</asp:TemplateField>
I have not tried this out, but it follows a similar pattern to what i have previously used. 我没有试过这个,但它遵循了我以前使用过的类似模式。 The code expression calls the codebehind function 'ShowButton' which should return a bool, here you can evaluate the value of process passed in, and if it is to your liking, pass back a true value;
代码表达式调用代码隐藏函数'ShowButton',它应该返回一个bool,在这里你可以评估传入的进程的值,如果它是你喜欢的,则传回一个真值; otherwise return false and the button will not show.
否则返回false,按钮不会显示。
C# C#
protected bool ShowButton(object DataItem)
{
//Here you can place as many conditions as you like
//Provided you always return either true or false
if (DataItem != null)
return true;
else
return false;
}
A suggested edit was posed in a similar fashion, however instead of a bool visibility, the visibility setting is altered by string value. 建议的编辑以类似的方式提出,但是不是bool可见性,而是通过字符串值更改可见性设置。 I am sure they will add their take too.
我相信他们也会加分。 After all, variety is the spice of life
毕竟,多样性是生活的调味品
Use codebehind, make the button visible when appropriate: 使用代码隐藏,在适当的时候使按钮可见:
protected void gridview1_RowDataBound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
DataRow row = ((DataRowView)e.Row.DataItem).Row;
string process = row.Field<string>("Process"); // change type from string to whatever it is
Button btn = (Button) e.Row.FindControl("ButtonID");
btn.Visible = process == "YourProcessValue";
}
}
you can make use of RowDataBoundand than make decision of hiding your control 你可以使用RowDataBoundand而不是决定隐藏你的控件
protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
SomeObject mapItem = (SomeObject)e.Row.DataItem;
if(!mapItem.Process)
(e.Row.Cells[3].FindControl("Buttonid") as Button).visible= false;
}
}
or try 或尝试
<ItemTemplate>
<asp:Button runat="server" Text="Reject"
Visible='<%# ((bool)Eval("Process")) %>' />
</ItemTemplate>
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