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Question

Hi im trying to write a program which uses a repetition statement to allow users to enter 5 numbers and stores them in a list.Then allow the user to search the list for a number entered by the user and indicate whether the number has been found or not. Im quite stuck on this one, I've made as much of an effort as i can

data =raw_input('Please input 5 numbers: ')
print data

search =raw_input('Search for the numer: ')
for sublist in data:
   if sublist[1] == search:
    print "Found it!", sublist
 break        

Answer 1

data is a string, the for loop will loop over every character in this string. That's probably not what you want.

If you want to find an integer in a list of integers, split the input on whitespace and convert each to an integer using int .

ints = [int(x) for x in data.split()]
if int(search) in ints:
    print "Found it"

Answer 2

You might try something like this

numbers = []

while len(numbers) < 5:
    number = raw_input('Please input 5 numbers: ')
    if number.isdigit():
        numbers.append(int(number)) #may want to use float here instead of int
    else:
        print "You entered something that isn't a number"

search = raw_input('Search for the numer: ')
if int(search) in numbers:
    print "Found it!"

your code indicates that you may be using sublists but it is unclear how you are creating them.

Answer 3

Issue 1 : This line stores the input as a string in the variable data .

data =raw_input('Please input 5 numbers: ')

At this point it is necessary to split the string into a list, and converting the elements to integers. If the user inputs numbers separated by a space, you can do:

data_list = data.split() # if the numbers are comma-separated do .split(',') instead
int_list = [int(element) for element in data_list]

Issue 2: The users search input should be converted to an integer

search =raw_input('Search for the numer: ')
search_int = int(search)

Issue 3: There is no need for indexing the sublist as you've attempted sublist[1] . The for-loop should then be:

for sublist in int_list:
    if sublist == search_int:
        print "Found it!", sublist
        break